Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 10 | 19 | 0.53 | 2.11% ▼ 33.3% vs last year |
| 2025 | 15 | 19 | 0.79 | 3.16% ▲ 11.5% vs last year |
| 2024 | 17 | 20 | 0.85 | 2.83% |
A card from a pack of 52 cards is lost. From the remaining 51 cards, n cards are drawn and are found to be spades. If the probability of the lost card to be a spade is 1150, then n is equal to .
Three balls are drawn at random from a bag containing 5 blue and 4 yellow balls. Let the random variables X and Y respectively denote the number of blue and yellow balls. If X and Y are the means of X and Y respectively, then 7 X + 4 Y is equal to .
From a lot of 12 items containing 3 defectives, a sample of 5 items is drawn at random. Let the random variable X denote the number of defective items in the sample. Let items in the sample be drawn one by one without replacement. If variance of X is mn, where (m, n) = 1, then n - m is equal to .
From a lot of 10 items, which include 3 defective items, a sample of 5 items is drawn at random. Let the random variable X denote the number of defective items in the sample. If the variance of X is 2, then 96 2 is equal to .
Let the mean and the standard deviation of the probability distribution [figure] be and , respectively. If - = 2, then + is equal to .
In a tournament, a team plays 10 matches with probabilities of winning and losing each match as 13 and 23 respectively. Let x be the number of matches that the team wins, and y be the number of matches that team loses. If the probability P(|x - y| 2) is p, then 39 p equals .
A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required and let a=P(X=3), b=P(X 3) and c=P(X 6 X>3). Then b+ca is equal to .