From a lot of 12 items containing 3 defectives, a sample of 5 items is drawn at random. Let the random variable X denote the number of defective items in the sample. Let items in the sample be drawn one by one without replacement. If variance of X is mn, where (m, n) = 1, then n - m is equal to .
Answer
71
Solution
3 defective + 9 good: P(X = k) = 3Ck 9C5-k 12C5, 12C5 = 792
P(0) = 126792 = 744, P(1) = 3 126792 = 2144
P(2) = 3 84792 = 1444, P(3) = 36792 = 244
E(X) = 21 + 28 + 644 = 54, E (X2 ) = 21 + 56 + 1844 = 9544
Var(X) = 9544 - 2516 = 380 - 275176 = 105176
m = 105, n = 176 (co-prime) n - m = 71
Answer: 71