Total number of unpaired electrons in the complex ions [Co(NH3)6]3+ and [NiCl4]2- is .
Coordination Compounds
Previous year questions with solutions · 2024 – 2026
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 33 | 19 | 1.7 | 6.95% ▼ 10.8% vs last year |
| 2025 | 37 | 19 | 1.9 | 7.79% ▲ 30% vs last year |
| 2024 | 36 | 21 | 1.7 | 5.99% |
Match List I with List II. Choose the correct answer from the options given below :
- A-IV, B-III, C-I, D-II
- A-III, B-I, C-IV, D-II
- A-I, B-III, C-IV, D-II
- A-III, B-IV, C-II, D-I
The correct order of ligands arranged in increasing field strength.
- F- < Br- < I- < NH3
- H2O < -OH < CN- < NH3
- Br- < F- < H2O < NH3
- Cl- < -OH < Br- < CN-
Which one of the following complexes will exhibit the least paramagnetic behaviour ? [Atomic number, Cr = 24, Mn = 25, Fe = 26, Co = 27]
- [Fe(H2O)6]2+
- [Mn(H2O)6]2+
- [Co(H2O)6]2+
- [Cr(H2O)6]2+
The number of complexes from the following with no electrons in the t2 orbital is . TiCl4, [MnO4]-, [FeO4]2-, [FeCl4]-, [CoCl4]2-
- 4
- 2
- 3
- 1
Number of complexes from the following with even number of unpaired "d" electrons is [V(H2O)6]3+, [Cr(H2O)6]2+, [Fe(H2O)6]3+, [Ni(H2O)6]3+, [Cu(H2O)6]2+ [Given atomic numbers: V = 23, Cr = 24, Fe = 26, Ni = 28, Cu = 29]
- 1
- 5
- 2
- 4
The correct sequence of ligands in the order of decreasing field strength is :
- NCS- > EDTA4- > CN- > CO
- CO > H2O > F- > S2-
- S2- > -OH > EDTA4- > CO
- -OH > F- > NH3 > CN-
If an iron (III) complex with the formula [Fe(NH3)x(CN)y]- has no electron in its eg orbital, then the value of x + y is
- 6
- 4
- 3
- 5
The number of unpaired d-electrons in [Co(H2O)6]3+ is .
- 0
- 2
- 1
- 4
The 'Spin only' Magnetic moment for [Ni(NH3)6]2+ is 10-1 BM. (given = Atomic number of Ni : 28)
Match List I with List II Choose the correct answer from the options given below:
- A-IV, B-I, C-II, D-III
- A-III, B-II, C-IV, D-I
- A-II, B-III, C-IV, D-I
- A-IV, B-III, C-I, D-II
Consider the following complex ions P = [FeF6]3- Q = [V(H2O)6]2+ R = [Fe(H2O)6]2+ The correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is :
- R < Q < P
- R < P < Q
- Q < R < P
- Q < P < R