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Complex Numbers and Quadratic Equations

JEE Main 2026 (Online) 21st January Evening ShiftMCQEasy📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2026, 21 January (Evening Shift)

Let and be the roots of the equation x2 + 2ax + (3a + 10) = 0 such that < 1 < . Then the set of all possible values of a is :

  1. (- , -115 ) (5, )
  2. (- , -115 )
  3. (- , -3)
  4. (- , -2) (5, )

Answer

(2) (- , -115 )

Solution

Let f(x) = x2 + 2ax + (3a + 10), an upward parabola, so 1 lies between the roots exactly when f(1) < 0:

1 + 2a + 3a + 10 < 0

5a + 11 < 0 a < - 115

(f(1) < 0 already ensures real, distinct roots.)

a (- , -115 )

Answer: (2)

Keep practising — Complex Numbers and Quadratic Equations

Ques. 2JEE Main 2026, 21 January (Evening Shift)

Let z be the complex number satisfying |z - 5| 3 and having maximum positive principal argument. Then 34 | 5z - 125iz + 16 |2 is equal to:

  1. 20
  2. 26
  3. 12
  4. 16
Ques. 3JEE Main 2025, 8 April (Evening Shift)

Let be a solution of x2 + x + 1 = 0, and for some a and b in R, bmatrix 4 & a & b bmatrix bmatrix 1 & 16 & 13 \ -1 & -1 & 2 \ -2 & -14 & -8 bmatrix = bmatrix 0 & 0 & 0 bmatrix. If 4 4 + m a + n b = 3, then m + n is equal to

  1. 11
  2. 3
  3. 8
  4. 7
Ques. 4JEE Main 2025, 8 April (Evening Shift)

The sum of the squares of the roots of |x-2|2 + |x-2| - 2 = 0 and the squares of the roots of x2 - 2|x-3| - 5 = 0, is

  1. 24
  2. 26
  3. 36
  4. 30
Ques. 5JEE Main 2025, 8 April (Evening Shift)

Let A = \ [0, 2 ] : 1 + 10 Re ( 2 + i - 3i ) = 0 \. Then A 2 is equal to

  1. 214 2
  2. 6 2
  3. 274 2
  4. 8 2
Ques. 6JEE Main 2025, 7 April (Morning Shift)

Let the set of all values of p R, for which both the roots of the equation x2 - (p + 2)x + (2p + 9) = 0 are negative real numbers, be the interval ( , ]. Then - 2 is equal to

  1. 5
  2. 0
  3. 20
  4. 9
Ques. 7JEE Main 2025, 7 April (Morning Shift)

Among the statements (S1) : The set \z C - \-i\ : |z| = 1 and z - iz + i is purely real \ contains exactly two elements, and (S2) : The set \z C - \-1\ : |z| = 1 and z - 1z + 1 is purely imaginary \ contains infinitely many elements.

  1. both are incorrect
  2. both are correct
  3. only (S2) is correct
  4. only (S1) is correct
Ques. 8JEE Main 2025, 7 April (Evening Shift)

If the locus of z C, such that Re ( z-12z+i ) + Re ( z-12 z-i ) = 2, is a circle of radius r and center (a, b), then 15abr2 is equal to :

  1. 16
  2. 24
  3. 12
  4. 18
Ques. 9JEE Main 2025, 7 April (Evening Shift)

The number of real roots of the equation x|x-2| + 3|x-3| + 1 = 0 is :

  1. 4
  2. 3
  3. 2
  4. 1
Ques. 10JEE Main 2025, 7 April (Evening Shift)

For t > -1, let t and t be the roots of the equation ((t + 2)1/7 - 1 )x2 + ((t + 2)1/6 - 1 )x + ((t + 2)1/21 - 1 ) = 0 If t -1+ t = a and t -1+ t = b, then 72(a + b)2 is equal to .

Ques. 11JEE Main 2025, 4 April (Morning Shift)

Consider the equation x2 + 4x - n = 0, where n [20, 100] is a natural number. Then the number of all distinct values of n, for which the given equation has integral roots, is equal to

  1. 6
  2. 5
  3. 8
  4. 7

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