The value of electric potential at a distance of 9 cm from the point charge 4 10-7 C is [Given 14 0 = 9 109 N m2 C-2]:
- 4 102 V
- 44.4 V
- 4.4 105 V
- 4 104 V
Answer
(4) 4 104 V
Solution
The potential of a point charge is V = 14 0 qr, so
V = 9 109 4 10-79 10-2
V = 4 104 V
Answer: (4)