The value of 01 (2x3-3x2-x+1 ) 13dx is equal to :
- -1
- 2
- 0
- 1
Answer
(3) 0
Solution
Put t=x- 12: 2x3-3x2-x+1=2t3- 52t=g(t), an odd function of t
f(1-x)=-f(x), where f(x)= (2x3-3x2-x+1 ) 13
01 f(x) dx= 01 f(1-x) dx=- 01 f(x) dx
2I=0 =0
Answer: (3)
The value of 01 (2x3-3x2-x+1 ) 13dx is equal to :
(3) 0
Put t=x- 12: 2x3-3x2-x+1=2t3- 52t=g(t), an odd function of t
f(1-x)=-f(x), where f(x)= (2x3-3x2-x+1 ) 13
01 f(x) dx= 01 f(1-x) dx=- 01 f(x) dx
2I=0 =0
Answer: (3)
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