Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Differential Equations

JEE Main 2025 (Online) 24th January Morning ShiftNumericalMedium📈 Topic in 67% papers+4
Ques. 1JEE Main 2025, 24 January (Morning Shift)

Let f be a differentiable function such that 2(x+2)2f(x)-3(x+2)2=10 0x(t+2)f(t) dt, x 0. Then f(2) is equal to .

Answer

19

Solution

Putting x=0 gives f(0)= 32. Differentiating and dividing by 2(x+2),

(x+2)f'=3(f+1) f'f+1= 3x+2

Integrating, f+1=C(x+2)3, and f(0)= 32 gives C= 516, so

f(2)+1= 516 64=20

f(2)=19

Answer: 19

Keep practising — Differential Equations

Ques. 2JEE Main 2025, 24 January (Evening Shift)

Let f:(0, ) be a function which is differentiable at all points of its domain and satisfies the condition x2f'(x)=2xf(x)+3, with f(1)=4. Then 2f(2) is equal to :

  1. 19
  2. 23
  3. 29
  4. 39
Ques. 3JEE Main 2025, 24 January (Evening Shift)

Let y=y(x) be the solution of the differential equation 2 x dydx= 2x-4y x, x (0, 2 ). If y ( 3 )=0, then y' ( 4 )+y ( 4 ) is equal to .

Ques. 4JEE Main 2025, 23 January (Morning Shift)

Let a curve y=f(x) pass through the points (0,5) and ( e 2,k). If the curve satisfies the differential equation 2(3+y)e2xdx-(7+e2x)dy=0, then k is equal to

  1. 32
  2. 8
  3. 4
  4. 16
Ques. 5JEE Main 2025, 23 January (Evening Shift)

Let x=x(y) be the solution of the differential equation y= (x-y dxdy ) ( xy ), y>0 and x(1)= 2. Then (x(2)) is equal to :

  1. 2 ( e 2 )-1
  2. 1-2 ( e 2 )2
  3. 1-2 ( e 2 )
  4. 2 ( e 2 )2-1
Ques. 6JEE Main 2025, 22 January (Morning Shift)

Let x=x(y) be the solution of the differential equation y2 dx+ (x- 1y )dy=0. If x(1)=1, then x ( 12 ) is :

  1. 32+e
  2. 12+e
  3. 3+e
  4. 3-e
Ques. 7JEE Main 2025, 22 January (Evening Shift)

If x=f(y) is the solution of the differential equation (1+y2 )+ (x-2e -1y ) dydx=0, y (- 2, 2 ) with f(0)=1, then f ( 1 3 ) is equal to :

  1. e /4
  2. e /12
  3. e /6
  4. e /3
Ques. 8JEE Main 2025, 22 January (Evening Shift)

Let y=f(x) be the solution of the differential equation dydx+ xyx2-1= x6+4x 1-x2, -1<x<1 such that f(0)=0. If 6 -1/21/2f(x) dx=2 - then 2 is equal to .

Ques. 9JEE Main 2024, 9 April (Morning Shift)

The solution of the differential equation (x2 + y2 )dx - 5xy dy = 0, y(1) = 0, is :

  1. |x2 - 4y2 |5 = x2
  2. |x2 - 2y2 |6 = x
  3. |x2 - 2y2 |5 = x2
  4. |x2 - 4y2 |6 = x
Ques. 10JEE Main 2024, 9 April (Morning Shift)

The solution curve, of the differential equation 2y dydx + 3 = 5 dydx, passing through the point (0, 1) is a conic, whose vertex lies on the line :

  1. 2x + 3y = -9
  2. 2x + 3y = -6
  3. 2x + 3y = 9
  4. 2x + 3y = 6
Ques. 11JEE Main 2024, 9 April (Evening Shift)

Let 0x 1 - (y'(t))2 dt = 0x y(t) dt, 0 x 3, y 0, y(0) = 0. Then at x = 2, y'' + y + 1 is equal to

  1. 2
  2. 2
  3. 1/2
  4. 1

All Differential Equations PYQs →

PDFDownload Differential Equations PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters