Let f be a differentiable function such that 2(x+2)2f(x)-3(x+2)2=10 0x(t+2)f(t) dt, x 0. Then f(2) is equal to .
Answer
19
Solution
Putting x=0 gives f(0)= 32. Differentiating and dividing by 2(x+2),
(x+2)f'=3(f+1) f'f+1= 3x+2
Integrating, f+1=C(x+2)3, and f(0)= 32 gives C= 516, so
f(2)+1= 516 64=20
f(2)=19
Answer: 19