When a string is divided into three segments of lengths l1, l2 and l3, the fundamental frequencies of these three segments are 1, 2 and 3 respectively. The original fundamental frequency ( ) of the string is
- = 1 + 2 + 3
- = 1 + 2 + 3
- 1 = 1 1 + 1 2 + 1 3
- 1 = 1 1 + 1 2 + 1 3
Answer
(3) 1 = 1 1 + 1 2 + 1 3
Solution
The fundamental frequency of a stretched string is = 12l T .
It is the same string, so T and are the same for every segment, which gives
l = k , where k = 12 T
l = l1 + l2 + l3,
k = k 1 + k 2 + k 3
1 = 1 1 + 1 2 + 1 3
Answer: (3)