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Integrals

JEE Main 2026 (Online) 21st January Morning ShiftNumericalMedium📈 Topic in 67% papers+4
Ques. 1JEE Main 2026, 21 January (Morning Shift)

6 0 |( 3x + 2x + x)| dx is equal to .

Answer

17

Solution

3x + x = 2 2x x, so

3x + 2x + x = 2x(2 x + 1) = 2 x x(2 x + 1)

On [0, ], x 0, so

I = 0 | 3x + 2x + x| dx = 0 2 x | x(2 x + 1)| dx

Putting x = t, - x dx = dt:

I = -11 2|t(2t + 1)| dt = 2 -11|2t2 + t| dt

2t2 + t 0 on [-1, - 12 ] and [0, 1], and 0 on [- 12, 0 ]. With F(t) = 2t33 + t22:

-1-1/2 = F (- 12 ) - F(-1) = 124 + 16 = 524

-1/20| | = |F(0) - F (- 12 ) | = 124

01 = F(1) = 23 + 12 = 2824

I = 2 ( 5 + 1 + 2824 ) = 176

6I = 17

Answer: 17

Keep practising — Integrals

Ques. 2JEE Main 2026, 21 January (Evening Shift)

Let [ ] denote the greatest integer function and f(x) = n 1n3 k=1n [ k23x ]. Then 12 j=1 f(j) is equal to .

Ques. 3JEE Main 2026, 21 January (Evening Shift)

If 01 4 -1 (1 - 2x + 4x2 )dx = a -1(2) - b e(5), where a, b N, then (2a + b) is equal to .

Ques. 4JEE Main 2025, 8 April (Evening Shift)

The integral -1 32 ( | 2 x ( x) | )dx is equal to:

  1. 2 + 3
  2. 4 +
  3. 1 + 3
  4. 3 + 2
Ques. 5JEE Main 2025, 8 April (Evening Shift)

Let f(x) be a positive function and I1 = - 121 2x f(2x(1 - 2x)) dx and I2 = -12 f(x(1 - x)) dx. Then the value of I2I1 is equal to

  1. 12
  2. 9
  3. 6
  4. 4
Ques. 6JEE Main 2025, 7 April (Morning Shift)

The integral 0 (x+3) x1+3 2 x dx is equal to

  1. 3( +1)
  2. 3 3( +6)
  3. 3( +2)
  4. 2 3( +4)
Ques. 7JEE Main 2025, 7 April (Evening Shift)

If ( 1x + 1x3 ) ( [23]3x-24 + x-26 ) dx = - 3( + 1) (3x + x ) + 1 + C, x > 0, ( , , Z), where C is the constant of integration, then + + is equal to .

Ques. 8JEE Main 2025, 4 April (Morning Shift)

The value of -11 (1 + |x| - x ) ex + ( |x| - x ) e-xex + e-x dx is equal to

  1. 1 + 2 23
  2. 1 - 2 23
  3. 2 + 2 23
  4. 3 - 2 23
Ques. 9JEE Main 2025, 4 April (Evening Shift)

Let f(x)+2f ( 1x )=x2+5 and 2g(x)-3g ( 12 )=x, x>0. If = 12 f(x) dx, and = 12 g(x) dx, then the value of 9 + is :

  1. 0
  2. 10
  3. 1
  4. 11
Ques. 10JEE Main 2025, 4 April (Evening Shift)

If ( 1+x2+x )10 ( 1+x2-x )9 dx= 1m ( ( 1+x2+x )n (n 1+x2-x ) )+C where C is the constant of integration and m, n N, then m+n is equal to .

Ques. 11JEE Main 2025, 3 April (Morning Shift)

Let f(x) = x3 3 - x2 dx. If 5f( 2) = -4, then f(1) is equal to

  1. - 6 25
  2. - 8 25
  3. - 2 25
  4. - 4 25

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