Let α and β respectively be the maximum and the minimum values of the function f( ) = 4 ( 4 ( 7 2 - ) + 4(11 + ) ) - 2 ( 6 ( 3 2 - ) + 6(9 - ) ), R. Then α + 2β is equal to :
- 6
- 5
- 4
- 3
Answer
(2) 5
Solution
Here ( 7 2 - ) = - , (11 + ) = - , ( 3 2 - ) = - and (9 - ) = , so
f( ) = 4 ( 4 + 4 ) - 2 ( 6 + 6 )
4 + 4 = 1 - 2 2 2 and 6 + 6 = 1 - 3 2 2 ,
f( ) = 4 - 8 2 2 - 2 + 6 2 2
= 2 - 2 2 2 = 2 - 12 2 2
Since 0 2 2 1, the maximum is = 2 and the minimum is = 32.
+ 2 = 2 + 3 = 5
Answer: (2)