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Binomial Theorem

JEE Main 2026 (Online) 8th April Evening ShiftMCQMedium📈 Topic in 43% papers+4−1
Ques. 1JEE Main 2026, 8 April (Evening Shift)

If 26 ( 233 (12C2 )+ 255 (12C4 )+ 277 (12C6 ) . .+ + 21313 (12C12 ) )=313- , then is equal to :

  1. 45
  2. 48
  3. 51
  4. 54

Answer

(3) 51

Solution

The general term is 2k + 1k + 1 (12Ck ), k = 2, 4, , 12.

1k + 1 12Ck = 113 13Ck + 1,

26 2k + 1k + 1 12Ck = 2 13Ck + 1 2k + 1

Putting r = k + 1 = 3, 5, , 13, LHS = 2 r = 3, 5, , 1313Cr 2r.

(1 + 2)13 - (1 - 2)13 = 2 r odd13Cr 2r, we get r odd13Cr 2r = 313 + 12.

The term r = 1 is 13C1 2 = 26, so

LHS = 2 ( 313 + 12 - 26 ) = 313 + 1 - 52 = 313 - 51

∴ = 51

Answer: (3)

Keep practising — Binomial Theorem

Ques. 2JEE Main 2026, 6 April (Morning Shift)

If the coefficients of the middle terms in the binomial expansions of (1+ x)26 and (1- x)28, 0, are equal, then the value of is :

  1. 1
  2. 1413
  3. 277
  4. 727
Ques. 3JEE Main 2026, 6 April (Evening Shift)

If (1-x3 )10= r=010arxr(1-x)30-2r, then 9a9a10 is equal to .

Ques. 4JEE Main 2026, 5 April (Morning Shift)

If the sum of the coefficients of x7 and x14 in the expansion of ( 1x3-x4 )n, x 0, is zero, then the value of n is .

Ques. 5JEE Main 2026, 5 April (Evening Shift)

The coefficient of x2 in the expansion of (2x2+ 1x )10, x 0, is :

  1. 3240
  2. 3360
  3. 3480
  4. 3600
Ques. 6JEE Main 2026, 4 April (Morning Shift)

Let the smallest value of k N, for which the coefficient of x3 in (1+x)3+(1+x)4+(1+x)5+ +(1+x)99+(1+kx)100, x 0, is (43n+ 1014 ) (100C3 ) for some n N, be p. Then the value of p+n is :

  1. 10
  2. 11
  3. 12
  4. 13
Ques. 7JEE Main 2026, 4 April (Evening Shift)

In the expansion of (9x- 13 x )18, x>0, if the term independent of x is (221)k, then k is equal to :

  1. 84
  2. 78
  3. 168
  4. 198
Ques. 8JEE Main 2026, 2 April (Morning Shift)

The number of elements in the set S= \(r,k) : k Z and 36Cr+1= 6 (35Cr ) (k2-3 ) \, is :

  1. 2
  2. 4
  3. 8
  4. 16
Ques. 9JEE Main 2026, 2 April (Evening Shift)

If for 3 r 30, (30C30-r )+3 (30C31-r )+3 (30C32-r )+ (30C33-r )=mCr, then m equals :

  1. 31
  2. 32
  3. 33
  4. 34
Ques. 10JEE Main 2026, 28 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are false
  3. Both Statement I and Statement II are true
  4. Statement I is true but Statement II is false
Ques. 11JEE Main 2026, 28 January (Evening Shift)

The sum of the coefficients of x499 and x500 in (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + + x1000 is :

  1. 1002C501
  2. 1001C501
  3. 1000C501
  4. 1002C500

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