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Semiconductor Electronics

AIPMT 2001MCQMedium📈 Topic in 25% papers+4−1
Ques. 1AIPMT 2001

The current in the circuit will be [figure]

  1. 540 A
  2. 550 A
  3. 510 A
  4. 520 A

Answer

(2) 550 A

Solution

The long plate (positive terminal) of the 5 V cell is on the left, so current leaves the cell towards the left junction and flows from left to right through the upper branches.

Diode D2 points from left to right ⇒ it is forward biased and conducts (ideal diode, zero resistance).

Diode D1 points from right to left ⇒ it is reverse biased, so no current flows through the upper 20 branch.

∴ Total resistance in the circuit = 20 + 30 = 50

⇒ I = VR = 550 A

Answer: (2)

Keep practising — Semiconductor Electronics

Ques. 2AIPMT 2001

For a common base circuit if ICIE = 0.98 then current gain for common emitter circuit will be

  1. 49
  2. 98
  3. 4.9
  4. 25.5
Out of syllabus
Ques. 3AIPMT 2000

From the following diode circuits, which diode is in forward biased condition?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4AIPMT 2000

The correct relation between and for a transistor is

  1. = 1-
  2. = 1-
  3. = -1
  4. = 1
Out of syllabus

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