If z is a complex number such that |z| 1, then the minimum value of |z+ 12(3+4 i) | is :
- 2
- 52
- 32
- 3
Answer
BONUS
Solution
|z+ 12(3+4i) |= |z- (- 32-2i ) | = distance of z from A (- 32,-2 )
[figure]
OA= 94+4= 52 1 A itself lies in the region |z| 1
Taking z=- 32-2i, the minimum value =0
0 is not among the options, no option is correct question dropped
Answer: Bonus (full marks to all who attempted)