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Limits and Derivatives

JEE Main 2026 (Online) 5th April Morning ShiftMCQMedium📈 Topic in 14% papers+4−1
Ques. 1JEE Main 2026, 5 April (Morning Shift)

The product of all possible values of , for which x 0 ( 1- ( x) (( +1)x) (( +2)x) 2(( +1)x) )=2, is :

  1. -2
  2. 1
  3. -1
  4. 54

Answer

(3) -1

Solution

For small x, (kx) = 1 - k2x22 + O (x4 ), so

( x) (( + 1)x) (( + 2)x) = 1 - [ 2 + ( + 1)2 + ( + 2)2 ]x22 + O (x4 )

and 2(( + 1)x) = ( + 1)2x2 + O (x4 ). Hence, for -1,

Limit = 2 + ( + 1)2 + ( + 2)22( + 1)2 = 2

3 2 + 6 + 5 = 4 2 + 8 + 4

2 + 2 - 1 = 0

Its roots -1 2 are real, distinct and neither equals -1.

∴ Product of all values of = -1

Answer: (3)

Keep practising — Limits and Derivatives

Ques. 2JEE Main 2026, 5 April (Evening Shift)

Let f(x)= y 0 (1- (xy)) (xy)y3. Then the number of solutions of the equation f(x)= x, x R is :

  1. 0
  2. 2
  3. 3
  4. 1
Ques. 3JEE Main 2026, 2 April (Morning Shift)

If x 2 (x3-5x2+ax+b ) ( x-1-1 ) e(x-1)=m, then a+b+m is equal to :

  1. 5
  2. 6
  3. 8
  4. 10
Ques. 4JEE Main 2026, 28 January (Morning Shift)

The value of x 0 e ( (ex) (e2x) (e10x) )e2 - e2 x is equal to

  1. (e10 - 1)2e2(e2 - 1)
  2. (e20 - 1)2e2(e2 - 1)
  3. (e10 - 1)2(e2 - 1)
  4. (e20 - 1)2(e2 - 1)
Ques. 5JEE Main 2026, 24 January (Morning Shift)

If the function f(x) = ex (e x - x - 1 ) + e( x + x) - x x - x is continuous at x = 0, then the value of f(0) is equal to

  1. 23
  2. 12
  3. 2
  4. 32
Ques. 6JEE Main 2026, 22 January (Evening Shift)

If x 0 e(a - 1)x + 2 bx + (c - 2)e-xx x - e(1 + x) = 2, then a2 + b2 + c2 is equal to :

  1. 3
  2. 5
  3. 9
  4. 7
Ques. 7JEE Main 2026, 21 January (Morning Shift)

Let f : R (0, ) be a twice differentiable function such that f(3) = 18, f'(3) = 0 and f''(3) = 4. Then x 1 e ( f(2 + x)f(3) ) 18(x - 1)2 is equal to :

  1. 9
  2. 18
  3. 1
  4. 2
Ques. 8JEE Main 2026, 21 January (Evening Shift)

Let f(x) = x3 + x2 f'(1) + 2x f''(2) + f'''(3), x R. Then the value of f'(5) is :

  1. 6575
  2. 1175
  3. 25
  4. 625
Ques. 9JEE Main 2025, 8 April (Evening Shift)

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below:

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are false
  3. Both Statement I and Statement II are true
  4. Statement I is true but Statement II is false
Ques. 10JEE Main 2025, 7 April (Morning Shift)

x 0+ (5(x) 13 ) e (1 + 3x2 ) ( -13 x )2 (e5(x) 43 - 1 ) is equal to

  1. 53
  2. 1
  3. 13
  4. 115
Ques. 11JEE Main 2025, 4 April (Morning Shift)

If x 1+ (x - 1)(6 + (x - 1)) + (1 - x)(x - 1)3 = -1, where , R, then + is equal to

  1. 20
  2. 19
  3. 18
  4. 17

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