In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width
(2) becomes four times
Fringe width: = Dd
New: D' = 2D, d' = d2
⇒ ' = (2D)d/2 = 4 Dd
∴ ' = 4
Answer: (2)
A parallel beam of light of wavelength is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
The angular resolution of a 10 cm diameter telescope at a wavelength of 5000 A is of the order of
A telescope has an objective lens of 10 cm diameter and is situated at a distance of one kilometer from two objects. The minimum distance between these two objects, which can be resolved by the telescope, when the mean wavelength of light is 5000 A, is of the order of
Diameter of human eye lens is 2 mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50 metre from the eye? The wavelength of light is 5000 Å.