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Current Electricity

AIPMT 2000MCQEasy📈 Topic in 38% papers+4−1
Ques. 1AIPMT 2000

Two bulbs of (40 W, 200 V), and (100 W, 200 V). Then correct relation for their resistances

  1. R40 < R100
  2. R40 > R100
  3. R40 = R100
  4. no relation can be predicted.

Answer

(2) R40 > R100

Solution

Resistance of a bulb from its rating: R = V2P

For the same rated voltage, R 1P

R40 = (200)240 = 1000 , R100 = (200)2100 = 400

R40 > R100

Answer: (2)

Keep practising — Current Electricity

Ques. 2AIPMT 2000

The potentiometer is best for measuring voltage, as

  1. it has a sensitive galvanometer and gives null deflection
  2. it has wire of high resistance
  3. it measures p.d. in closed circuit
  4. it measures p.d. in open circuit.

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