Let the lines 3x-4y- =0, 8x-11y-33=0, and 2x-3y+ =0 be concurrent. If the image of the point (1,2) in the line 2x-3y+ =0 is ( 5713, -4013 ), then | | is equal to
(1) 91
The mirror is the perpendicular bisector of PQ, so the midpoint M lies on it.
[figure]
M= ( 3513,- 713 ) on 2x-3y+ =0: 70+2113+ =0 =-7
8x-11y=33 and 2x-3y=7 meet at (11,5)
Concurrent 33-20- =0 =13
| |=13 7=91
Answer: (1)
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