If power dissipated in the 9 Ω resistor in the circuit shown is 36 watt, the potential difference across the 2 Ω resistor is [figure]
- 4 volt
- 8 volt
- 10 volt
- 2 volt
Answer
(3) 10 volt
Solution
For the 9 Ω resistor, P = V2R, so
36 = V29 V = 18 V
The 6 Ω resistor is in parallel, so it also has 18 V across it; hence I9 = 189 = 2 A and I6 = 186 = 3 A.
The current through the 2 Ω resistor is therefore 2 + 3 = 5 A.
Potential difference across 2 Ω = 5 2 = 10 V
Answer: (3)