In a region, the potential is represented by V(x, y, z) = 6x - 8xy - 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is
- 6 5 N
- 30 N
- 24 N
- 4 35 N
Answer
(4) 4 35 N
Solution
The field is E = - ( V x i + V y j + V z k ).
At (1, 1, 1), V x = 6 - 8y = -2, V y = -8x - 8 + 6z = -10 and V z = 6y = 6, so
E = 2 i + 10 j - 6 k
| E| = 4 + 100 + 36 = 140 = 2 35 V m-1
F = qE = 2 2 35 = 4 35 N
Answer: (4)