A bag contains (N+1) coins - N fair coins, and one coin with 'Head' on both sides. A coin is selected at random and tossed. If the probability of getting 'Head' is 916, then N is equal to :
- 5
- 7
- 8
- 9
Answer
(2) 7
Solution
Let E1 be the event that a fair coin is chosen, with P (E1 ) = NN + 1 and P (H|E1 ) = 12, and E2 the event that the two-headed coin is chosen, with P (E2 ) = 1N + 1 and P (H|E2 ) = 1.
By total probability,
P(H) = NN + 1 12 + 1N + 1 1 = N + 22(N + 1) = 916
16N + 32 = 18N + 18
2N = 14 N = 7
Answer: (2)