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Statistics

JEE Main 2025 (Online) 4th April Evening ShiftMCQMedium📈 Topic in 13% papers+4−1
Ques. 1JEE Main 2025, 4 April (Evening Shift)

Let the mean and the standard deviation of the observations 2, 3, 3, 4, 5, 7, a, b be 4 and 2 respectively. Then the mean deviation about the mode of these observations is :

  1. 12
  2. 34
  3. 1
  4. 2

Answer

(3) 1

Solution

Mean = 4 2 + 3 + 3 + 4 + 5 + 7 + a + b = 8 4 = 32

24 + a + b = 32 a + b = 8

Variance = xi28 - (mean)2 = 2

xi2 = 8(2 + 16) = 144

4 + 9 + 9 + 16 + 25 + 49 + a2 + b2 = 144 a2 + b2 = 32

2ab = (a + b)2 - (a2 + b2) = 64 - 32 = 32 ab = 16

(a - b)2 = 64 - 64 = 0 a = b = 4

Observations: 2, 3, 3, 4, 4, 4, 5, 7 mode = 4

|xi - 4| = 2 + 1 + 1 + 0 + 0 + 0 + 1 + 3 = 8

Mean deviation about mode = 88 = 1

Answer: (3)

Keep practising — Statistics

Ques. 2JEE Main 2025, 3 April (Evening Shift)

Let the Mean and Variance of five observations x1 = 1, x2 = 3, x3 = a, x4 = 7 and x5 = b, a > b, be 5 and 10 respectively. Then the Variance of the observations n + xn, n = 1, 2, , 5 is

  1. 17
  2. 16
  3. 16.4
  4. 17.4
Ques. 3JEE Main 2025, 2 April (Evening Shift)

If the mean and the variance of 6, 4, a, 8, b, 12, 10, 13 are 9 and 9.25 respectively, then a + b + ab is equal to :

  1. 103
  2. 106
  3. 100
  4. 105
Ques. 4JEE Main 2025, 29 January (Morning Shift)

Let x1, x2, , x10 be ten observations such that i=110(xi - 2) = 30, i=110(xi - )2 = 98, > 2, and their variance is 45. If and 2 are respectively the mean and the variance of 2(x1 - 1) + 4 , 2(x2 - 1) + 4 , , 2(x10 - 1) + 4 , then 2 is equal to :

  1. 100
  2. 90
  3. 120
  4. 110
Ques. 5JEE Main 2025, 24 January (Morning Shift)

For a statistical data x1, x2, , x10 of 10 values, a student obtained the mean as 5.5 and i=110xi2=371. He later found that he had noted two values in the data incorrectly as 4 and 5, instead of the correct values 6 and 8, respectively. The variance of the corrected data is

  1. 5
  2. 7
  3. 9
  4. 4
Ques. 6JEE Main 2025, 23 January (Morning Shift)

Marks obtains by all the students of class 12 are presented in a freqency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12. If the number of students whose marks are less than 12 is 18 , then the total number of students is :

  1. 52
  2. 44
  3. 40
  4. 48
Ques. 7JEE Main 2025, 23 January (Evening Shift)

The variance of the numbers 8, 21, 34, 47, , 320 is .

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