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Semiconductor Electronics

AIPMT 2011 (Mains)MCQEasy📈 Topic in 62% papers+4−1
Ques. 1AIPMT 2011 (Mains)

A Zener diode, having breakdown voltage equal to 15 V, is used in a voltage regulator circuit shown in figure. The current through the diode is [figure]

  1. 5 mA
  2. 10 mA
  3. 15 mA
  4. 20 mA

Answer

(1) 5 mA

Solution

The Zener diode is in breakdown, so the voltage across it and across the 1 kΩ load is 15 V.

Current through the load: IL = 151000 = 15 mA

Voltage across the 250 Ω resistor = 20 - 15 = 5 V

I = 5250 = 0.02 A = 20 mA

IZ = I - IL = 20 - 15 = 5 mA

Answer: (1)

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Ques. 2AIPMT 2011 (Mains)

In the following figure, the diodes which are forward biased, are [figure]

  1. (A), (B) and (D)
  2. (C) only
  3. (C) and (A)
  4. (B) and (D)
Ques. 3AIPMT 2011 (Mains)

Pure Si at 500 K has equal number of electron (ne) and hole (nh) concentrations of 1.5 1016 m-3. Doping by indium increases nh to 4.5 1022 m-3. The doped semiconductor is of

  1. p-type having electron concentration ne = 5 109 m-3
  2. n-type with electron concentration ne = 5 1022 m-3
  3. p-type with electron concentration ne = 2.5 1010 m-3
  4. n-type with electron concentration ne = 2.5 1023 m-3
Ques. 4AIPMT 2011 (Prelims)

In forward biasing of the p-n junction

  1. the positive terminal of the battery is connected to p-side and the depletion region becomes thick.
  2. the positive terminal of the battery is connected to n-side and the depletion region becomes thin.
  3. the positive terminal of the battery is connected to n-side and the depletion region becomes thick.
  4. the positive terminal of the battery is connected to p-side and the depletion region becomes thin.
Ques. 5AIPMT 2011 (Prelims)

Symbolic representations of four logic gates are shown as [figure] Pick out which ones are for AND, NAND and NOT gates, respectively

  1. (ii), (iii) and (iv)
  2. (iii), (ii) and (i)
  3. (iii), (ii) and (iv)
  4. (iii), (iv) and (ii)
Ques. 6AIPMT 2011 (Prelims)

If a small amount of antimony is added to germanium crystal

  1. it becomes a p-type semiconductor
  2. the antimony becomes an acceptor atom
  3. there will be more free electrons than holes in the semiconductor
  4. its resistance is increased
Ques. 7AIPMT 2011 (Prelims)

A transistor is operated in common emitter configuration at VC = 2 V such that a change in the base current from 100 A to 300 A produces a change in the collector current from 10 mA to 20 mA. The current gain is

  1. 50
  2. 75
  3. 100
  4. 25
Out of syllabus
Ques. 8AIPMT 2010 (Mains)

The following figure shows a logic gate circuit with two inputs A and B and the output Y. The voltage waveforms of A, B and Y are as given. [figure] The logic gate is

  1. NOR gate
  2. OR gate
  3. AND gate
  4. NAND gate
Ques. 9AIPMT 2010 (Mains)

For transistor action Which one of the following pairs of statements is correct?

  1. D and A
  2. A and B
  3. B and C
  4. C and D
Out of syllabus
Ques. 10AIPMT 2010 (Prelims)

To get an output Y = 1 in given circuit which of the following input will be correct? [figure]

  1. A 1, B 0, C 0
  2. A 1, B 0, C 1
  3. A 1, B 1, C 0
  4. A 0, B 1, C 0
Ques. 11AIPMT 2010 (Prelims)

Which one of the following statements is false?

  1. Pure Si doped with trivalent impurities gives a p-type semiconductor.
  2. Majority carriers in a n-type semiconductor are holes.
  3. Minority carriers in a p-type semiconductor are electrons.
  4. The resistance of intrinsic semiconductor decreases with increase of temperature.

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