The net impedance of circuit (as shown in figure) will be : [figure]
- 15
- 5 5
- 25
- 10 2
Answer
(2) 5 5
Solution
The inductive reactance is
XL = 2 fL = 2 50 50 10-3
XL = 5
and the capacitive reactance is
XC = 12 fC = 12 50 103 10-6
XC = 10.1 = 10
For the series circuit, Z = R2 + (XC - XL)2, so
Z = 102 + 52 = 125
Z = 5 5
Answer: (2)