The unit of permittivity of free space, 0, is
- coulomb/newton-metre
- newton-metre2/coulomb2
- coulomb2/newton-metre2
- coulomb2/(newton-metre)2
Answer
(3) coulomb2/newton-metre2
Solution
From Coulomb's law, F = 14 0 q1 q2r2, so
0 = q1 q24 F r2
Hence the unit of 0 is C2N m2, i.e. coulomb2/newton-metre2.
Answer: (3)