Let a=2 i+3 j+3 k and b=6 i+3 j+3 k. Then the square of the area of the triangle with adjacent sides determined by the vectors (2 a+3 b ) and ( a- b ) is :
- 450
- 900
- 1800
- 2400
Answer
(3) 1800
Solution
a a = b b = 0,
(2 a + 3 b ) ( a - b ) = -2 a b + 3 b a
(2 a + 3 b ) ( a - b ) = -5 ( a b )
Now a b = vmatrix i & j & k\ 2 & 3 & 3\ 6 & 3 & 3 vmatrix = 0 i + 12 j - 12 k, so | a b | = 12 2.
Hence the area of the triangle = 12 5 12 2 = 30 2.
∴ (Area)2 = 900 2 = 1800
Answer: (3)