Let y = y(x) be the solution of the differential equation x4 dy + (4x3y + 2 x) dx = 0, x > 0, y ( 2 ) = 0. Then 4 y ( 3 ) is equal to :
- 92
- 72
- 64
- 81
Answer
(4) 81
Solution
Rearranging, x4 dy + 4x3y dx = -2 x dx, and the left side is an exact differential:
d(x4y) = -2 x dx
Integrating, x4y = 2 x + C.
y ( 2 ) = 0 gives 0 = 2 2 + C, so C = 0 and x4y = 2 x.
At x = 3: 481 y ( 3 ) = 2 12 = 1
4 y ( 3 ) = 81
Answer: (4)