Radioactive material 'A' has decay constant '8 ' and material 'B' has decay constant ' '. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that of 'A' will be e ?
- 17
- 18
- 19
- 1
Answer
(1) 17
Solution
NA = N0 e-8 t and NB = N0 e- t, so
NBNA = e- te-8 t = e7 t
This ratio is given as e, hence
e7 t = e1
7 t = 1
∴ t = 17
Answer: (1)