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Relations and Functions (Class 12)

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 48% papers+4−1
Ques. 1JEE Main 2025, 2 April (Morning Shift)

Let A be the set of all functions f : Z Z and R be a relation on A such that R = \(f, g) : f(0) = g(1) and f(1) = g(0)\. Then R is :

  1. Symmetric and transitive but not reflexive
  2. Symmetric but neither reflexive nor transitive
  3. Transitive but neither reflexive nor symmetric
  4. Reflexive but neither symmetric nor transitive

Answer

(2) Symmetric but neither reflexive nor transitive

Solution

Reflexive: (f, f) R needs f(0) = f(1), which fails for f(x) = x.

R is not reflexive.

Symmetric: (f, g) R f(0) = g(1), f(1) = g(0)

g(0) = f(1), g(1) = f(0) (g, f) R

R is symmetric.

Transitive: take f(x) = x + 1 and g(x) = 2 - x.

f(0) = 1 = g(1) and f(1) = 2 = g(0) (f, g) R; by symmetry (g, f) R.

But (f, f) R since f(0) = 1 2 = f(1).

R is not transitive.

Answer: (2)

Keep practising — Relations and Functions (Class 12)

Ques. 2JEE Main 2025, 29 January (Morning Shift)

Define a relation R on the interval [0, 2 ) by x R y if and only if 2 x - 2 y = 1. Then R is :

  1. both reflexive and symmetric but not transitive
  2. both reflexive and transitive but not symmetric
  3. reflexive but neither symmetric nor transitive
  4. an equivalence relation
Ques. 3JEE Main 2025, 28 January (Morning Shift)

If f(x) = 2x2x + 2, x R, then k=181 f ( k82 ) is equal to

  1. 82
  2. 81 2
  3. 41
  4. 812
Ques. 4JEE Main 2025, 28 January (Morning Shift)

The relation R = \(x, y) : x, y Z and x + y is even\ is:

  1. reflexive and transitive but not symmetric
  2. reflexive and symmetric but not transitive
  3. an equivalence relation
  4. symmetric and transitive but not reflexive
Ques. 5JEE Main 2025, 28 January (Evening Shift)

Let f: R - \0\ (- , 1) be a polynomial of degree 2, satisfying f(x)f ( 1x ) = f(x) + f ( 1x ). If f(K) = -2K, then the sum of squares of all possible values of K is:

  1. 9
  2. 1
  3. 6
  4. 7
Ques. 6JEE Main 2025, 28 January (Evening Shift)

Let f : [0, 3] A be defined by f(x) = 2x3 - 15x2 + 36x + 7 and g : [0, ) B be defined by g(x) = x2025x2025 + 1. If both the functions are onto and S = \x Z; x A or x B\, then n(S) is equal to :

  1. 29
  2. 31
  3. 30
  4. 36
Ques. 7JEE Main 2025, 24 January (Morning Shift)

Let f:R-\0\ be a function such that f(x)-6f ( 1x )= 353x- 52. If x 0 ( 1 x+f(x) )= ; , , then +2 is equal to

  1. 6
  2. 5
  3. 3
  4. 4
Ques. 8JEE Main 2025, 24 January (Morning Shift)

Let f(x)= 2x+2+1622x+1+2x+4+32. Then the value of 8 (f ( 115 )+f ( 215 )+ +f ( 5915 ) ) is equal to

  1. 108
  2. 92
  3. 118
  4. 102
Ques. 9JEE Main 2025, 24 January (Evening Shift)

The function f:(- , ) (- ,1), defined by f(x)= 2x-2-x2x+2-x is :

  1. One-one but not onto
  2. Onto but not one-one
  3. Both one-one and onto
  4. Neither one-one nor onto
Ques. 10JEE Main 2025, 24 January (Evening Shift)

Number of functions f:\1,2, ,100\ \0,1\, that assign 1 to exactly one of the positive integers less than or equal to 98, is equal to .

Ques. 11JEE Main 2025, 23 January (Morning Shift)

Let R=\(1,2),(2,3),(3,3)\ be a relation defined on the set \1,2,3,4\. Then the minimum number of elements, needed to be added in R so that R becomes an equivalence relation, is:

  1. 9
  2. 8
  3. 7
  4. 10

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