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Inverse Trigonometric Functions

JEE Main 2025 (Online) 28th January Evening ShiftMCQEasy📈 Topic in 11% papers+4−1
Ques. 1JEE Main 2025, 28 January (Evening Shift)

Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = -1(2[x] + 1) is:

  1. (- , )
  2. (- , ) - \0\
  3. (- , -1] [0, )
  4. (- , -1] [1, )

Answer

(1) (- , )

Solution

-1t is defined for |t| 1, i.e. t -1 or t 1.

2[x] + 1 1 [x] 0 x 0

2[x] + 1 -1 [x] -1 x < 0

Domain = (- , 0) [0, ) = (- , )

(Indeed, 2[x] + 1 is always an odd integer, so |2[x] + 1| 1 for every real x.)

Answer: (1)

Keep practising — Inverse Trigonometric Functions

Ques. 2JEE Main 2025, 24 January (Morning Shift)

If for some , ; , + =8 and 2 ( -1 )+cosec2 ( -1 )=36, then 2+ is

Ques. 3JEE Main 2025, 24 January (Evening Shift)

If > > >0, then the expression -1 \ + (1+ 2)( - ) \+ -1 \ + (1+ 2)( - ) \ + -1 \ + (1+ 2)( - ) \ is equal to :

  1. 3
  2. 2-( + + )
  3. 0
Ques. 4JEE Main 2025, 23 January (Morning Shift)

If 2 x 3 4, then -1 ( 1213 x+ 513 x ) is equal to

  1. x+ -1 512
  2. x- -1 43
  3. x+ -1 45
  4. x- -1 512
Ques. 5JEE Main 2025, 22 January (Morning Shift)

Using the principal values of the inverse trigonometric functions, the sum of the maximum and the minimum values of 16 ( ( -1x )2+ ( cosec-1x )2 ) is :

  1. 24 2
  2. 18 2
  3. 22 2
  4. 31 2

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