If the system of linear equations : x+y+2z=6 2x+3y+az=a+1 -x-3y+bz=2b where a,b , has infinitely many solutions, then 7a+3b is equal to :
- 12
- 9
- 22
- 16
Answer
(4) 16
Solution
R2-2R1: y+(a-4)z=a-11
R3+R1: -2y+(b+2)z=2b+6
Eliminate y: (2a+b-6) z=2a+2b-16
Infinitely many solutions both sides =0
2a+b=6, 2a+2b=16
b=10, a=-2
7a+3b=-14+30=16
Answer: (4)