The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = x + 3. The displacement of the particle when its velocity is zero, will be
- 4 m
- 0 m (zero)
- 6 m
- 2 m
Answer
(2) 0 m (zero)
Solution
Given x = t - 3,
x = (t - 3)2
v = dxdt = 2(t - 3)
so v = 0 at t = 3 s.
x = (3 - 3)2 = 0 m
Answer: (2)