x 0 cosecx ( 2 2x+3 x- 2x+ x+4 ) is
- 1 15
- 12 5
- 0
- - 12 5
Answer
(4) - 12 5
Solution
Both roots 5 and cosecx : rationalise.
L= x 0 ( x-1)( x+4)- x x ( 2 2x+3 x+ 2x+ x+4 )
x-1 x=- x2 0
L= 0-1 5+ 5=- 12 5
Answer: (4)
x 0 cosecx ( 2 2x+3 x- 2x+ x+4 ) is
(4) - 12 5
Both roots 5 and cosecx : rationalise.
L= x 0 ( x-1)( x+4)- x x ( 2 2x+3 x+ 2x+ x+4 )
x-1 x=- x2 0
L= 0-1 5+ 5=- 12 5
Answer: (4)
x (2x2-3x+5 )(3x-1) x2 (3x2+5x+4 ) (3x+2)x is equal to :
If x ( ( e1-e ) ( 1e- x1+x ) )x= , then the value of e 1+ e equals :
The value of x 0 2 ( 1 - x 2x [3] 3x [10] 10xx2 ) is .
If = x 0+ ( e x - e x x - x ) and = x 0(1 + x) 12 x are the roots of the quadratic equation ax2 + bx - e = 0, then 12 e(a + b) is equal to .
Let a > 0 be a root of the equation 2x2 + x - 2 = 0. If x 1a 16 (1 - (2 + x - 2x2 ) )(1 - ax)2 = + 17, where , Z, then + is equal to .
If x 1 (5x+1)1/3-(x+5)1/3(2x+3)1/2-(x+4)1/2= m 5n(2n)2/3, where (m, n)=1, then 8m+12n is equal to .
Let f(x) = 0x (t + (1 - et ) )dt, x R. Then, x 0 f(x)x3 is equal to
Let \x\ denote the fractional part of x and f(x)= -1 (1-\x\2 ) -1(1-\x\)\x\-\x\3, x 0. If L and R respectively denotes the left hand limit and the right hand limit of f(x) at x=0, then 32 2 (L2+R2 ) is equal to .
Let f(x)= casesx-1, & x is even,\ 2x, & x is odd, cases x . If for some a , f(f(f(a)))=21, then x - \ |x|3a- [ xa ] \, where [t] denotes the greatest integer less than or equal to t, is equal to :