A particle moves along a circle of radius ( 20 ) m with constant tangential acceleration. If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is
- 40 m/s2
- 640 m/s2
- 160 m/s2
- 40 m/s2
Answer
(1) 40 m/s2
Solution
In 2 revolutions the particle covers a distance along the circle
s = 2 2 r = 4 20 = 80 m
The tangential acceleration is constant and the particle starts from rest, so v2 = u2 + 2at s gives
(80)2 = 0 + 2at 80
at = 6400160 = 40 m/s2
Answer: (1)