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JEE Main 2026 (Online) 22nd January Evening ShiftNumericalEasy📈 Topic in 5% papers+4
Ques. 1JEE Main 2026, 22 January (Evening Shift)

Let S be the set of the first 11 natural numbers. Then the number of elements in A = \B S : n(B) 2 and the product of all elements of B is even\ is .

Answer

1979

Solution

S = \1, 2, , 11\ has 5 even and 6 odd numbers.

The product of the elements of B is even B contains at least one even number.

Non-empty subsets with at least one even number = 211 - 26 = 2048 - 64 = 1984

(all subsets minus the subsets made of odd numbers only, including )

Of these, subsets with only one element are \2\, \4\, \6\, \8\, \10\, i.e. 5.

n(A) = 1984 - 5 = 1979

Answer: 1979

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Ques. 2JEE Main 2026, 21 January (Evening Shift)

Let A = \x : |x2 - 10| 6\ and B = \x : |x - 2| > 1\. Then

  1. A B = (- , 1] (2, )
  2. B - A = (- , -4) (-2, 1) (4, )
  3. A - B = [2, 3)
  4. A B = [-4, -2] [3, 4]
Ques. 3JEE Main 2025, 7 April (Evening Shift)

Let A = \( , ) R R : | - 1| 4 and | - 5| 6\ and B = \( , ) R R : 16( - 2)2 + 9( - 6)2 144\. Then

  1. A B
  2. B A
  3. neither A B nor B A
  4. A B = \(x, y) : -4 x 4, -1 y 11\
Ques. 4JEE Main 2025, 4 April (Morning Shift)

Let A = \1, 6, 11, 16, \ and B = \9, 16, 23, 30, \ be the sets consisting of the first 2025 terms of two arithmetic progressions. Then n(A B) is

  1. 3814
  2. 4003
  3. 4027
  4. 3761
Ques. 5JEE Main 2025, 23 January (Evening Shift)

Let A=\(x,y) :|x+y| 3\ and B=\(x,y) :|x|+|y| 3\. If C=\(x,y) :x=0 or y=0\, then (x,y) |x+y| is :

  1. 18
  2. 24
  3. 15
  4. 12
Ques. 6JEE Main 2025, 22 January (Morning Shift)

Let A=\1,2,3, ,10\ and B= \ mn:m,n A, m<n and (m,n)=1 \. Then n(B) is equal to :

  1. 29
  2. 31
  3. 37
  4. 36

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