If x=f(y) is the solution of the differential equation (1+y2 )+ (x-2e -1y ) dydx=0, y (- 2, 2 ) with f(0)=1, then f ( 1 3 ) is equal to :
- e /4
- e /12
- e /6
- e /3
Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 24 | 19 | 1.3 | 5.05% same as last year |
| 2025 | 24 | 19 | 1.3 | 5.05% ▼ 24.2% vs last year |
| 2024 | 40 | 20 | 2 | 6.67% |
If x=f(y) is the solution of the differential equation (1+y2 )+ (x-2e -1y ) dydx=0, y (- 2, 2 ) with f(0)=1, then f ( 1 3 ) is equal to :
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