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Differential Equations

Previous year questions with solutions · 2024 – 2026

88Questions
58Papers covered
5.05%Weightage 2026same as last year
’24
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
202624191.35.05% same as last year
202524191.35.05% ▼ 24.2% vs last year
2024402026.67%

47 questions · newest paper first · page 2 of 2

Ques. 31JEE Main 2025, 22 January (Evening Shift)

If x=f(y) is the solution of the differential equation (1+y2 )+ (x-2e -1y ) dydx=0, y (- 2, 2 ) with f(0)=1, then f ( 1 3 ) is equal to :

  1. e /4
  2. e /12
  3. e /6
  4. e /3
Ques. 32JEE Main 2025, 22 January (Evening Shift)

Let y=f(x) be the solution of the differential equation dydx+ xyx2-1= x6+4x 1-x2, -1<x<1 such that f(0)=0. If 6 -1/21/2f(x) dx=2 - then 2 is equal to .

Ques. 33JEE Main 2024, 9 April (Evening Shift)

For a differentiable function f : R R, suppose f'(x) = 3f(x) + , where R, f(0) = 1 and x - f(x) = 7. Then 9f(- e 3) is equal to .

Ques. 34JEE Main 2024, 8 April (Evening Shift)

Let y = y(x) be the solution curve of the differential equation y dydx + 2x y = x3 y, y(1) = 0. Then y( 3) is equal to:

  1. 6
  2. 12
  3. 3
  4. 4
Ques. 35JEE Main 2024, 6 April (Morning Shift)

Let y = y(x) be the solution of the differential equation (2x e x) dydx + 2y = 3x e x, x > 0 and y (e-1 ) = 0. Then, y(e) is equal to

  1. - 3e
  2. - 32e
  3. - 23e
  4. - 2e
Ques. 36JEE Main 2024, 6 April (Morning Shift)

Let y = y(x) be the solution of the differential equation (1 + x2 ) dydx + y = e -1x, y(1) = 0. Then y(0) is

  1. 14 (e /2 - 1 )
  2. 12 (1 - e /2 )
  3. 14 (1 - e /2 )
  4. 12 (e /2 - 1 )
Ques. 37JEE Main 2024, 5 April (Morning Shift)

If y = y(x) is the solution of the differential equation dydx + 2y = (2x), y(0) = 34, then y ( 8 ) is equal to :

  1. e- /8
  2. e /4
  3. e- /4
  4. e /8
Ques. 38JEE Main 2024, 5 April (Morning Shift)

Let f be a differentiable function in the interval (0, ) such that f(1) = 1 and t x t2 f(x) - x2 f(t)t - x = 1 for each x > 0. Then 2f(2) + 3f(3) is equal to .

Ques. 39JEE Main 2024, 5 April (Evening Shift)

Let y = y(x) be the solution of the differential equation dydx + 2x (1 + x2 )2y = xe 1 (1 + x2 ); y(0) = 0. Then the area enclosed by the curve f(x) = y(x)e- 1 (1 + x2 ) and the line y - x = 4 is .

Ques. 40JEE Main 2024, 4 April (Morning Shift)

Let the solution y=y(x) of the differential equation dydx-y=1+4 x satisfy y( )=1. Then y ( 2 )+10 is equal to .

Ques. 41JEE Main 2024, 4 April (Evening Shift)

Let y = y(x) be the solution of the differential equation (x2 + 4)2dy + (2x3y + 8xy - 2)dx = 0. If y(0) = 0, then y(2) is equal to

  1. 2
  2. 8
  3. 16
  4. 32
Ques. 42JEE Main 2024, 1 February (Morning Shift)

If x=x(t) is the solution of the differential equation (t+1)dx= (2x+(t+1)4 )dt, x(0)=2, then, x(1) equals .

Ques. 43JEE Main 2024, 1 February (Evening Shift)

Let be a non-zero real number. Suppose f: R R is a differentiable function such that f(0)=2 and x - f(x)=1. If f (x)= f(x)+3, for all x R, then f (- e 2 ) is equal to :

  1. 7
  2. 9
  3. 3
  4. 5
Ques. 44JEE Main 2024, 1 February (Evening Shift)

If dxdy= 1+x-y2y,x(1)=1, then 5x(2) is equal to .

Ques. 45JEE Main 2024, 31 January (Morning Shift)

Let y=y(x) be the solution of the differential equation dydx= ( x)+y x( x- x x), x (0, 2 ) satisfying the condition y ( 4 )=2. Then, y ( 3 ) is

  1. 3 (2+ e 3 )
  2. 3 (1+2 e 3 )
  3. 3 (2+ e 3 )
  4. 32 (2+ e 3 )
Ques. 46JEE Main 2024, 30 January (Morning Shift)

Let y=y(x) be the solution of the differential equation (1-x2 )dy= [xy+ (x3+2 ) 3 (1-x2 ) ]dx, -1<x<1, y(0)=0. If y ( 12 )= mn, m and n are co-prime numbers, then m+n is equal to .

Ques. 47JEE Main 2024, 29 January (Morning Shift)

A function y=f(x) satisfies f(x) 2x+ x- (1+ 2x )f'(x)=0 with condition f(0)=0. Then, f ( 2 ) is equal to

  1. 2
  2. 1
  3. -1
  4. 0