Let O be the origin, the point A be z1 = 3 + 2 2i, the point B(z2) be such that 3|z2| = |z1| and (z2) = (z1) + 6. Then
- area of triangle ABO is 114
- area of triangle ABO is 11 3
- ABO is a scalene triangle
- ABO is an obtuse angled isosceles triangle
Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 36 | 19 | 1.9 | 7.58% ▲ 2.9% vs last year |
| 2025 | 35 | 19 | 1.8 | 7.37% ▲ 0.5% vs last year |
| 2024 | 44 | 20 | 2.2 | 7.33% |
Let O be the origin, the point A be z1 = 3 + 2 2i, the point B(z2) be such that 3|z2| = |z1| and (z2) = (z1) + 6. Then
If + i and + i are the roots of x2 - (3 - 2i)x - (2i - 2) = 0, i = -1, then + is equal to:
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Let | z-i2 z+i |= 13, z C, be the equation of a circle with center at C. If the area of the triangle, whose vertices are at the points (0,0), C and ( ,0) is 11 square units, then 2 equals:
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Let and be the distinct roots of 2x2+( )x-1=0, (0,2 ). If m and M are the minimum and the maximum values of 4+ 4, then 16(M+m) equals :
Let the curve z(1+i)+ z(1-i)=4, z , divide the region |z-3| 1 into two parts of areas and . Then | - | equals :
Let , be the roots of the equation x2 + 2 2x - 1 = 0. The quadratic equation, whose roots are 4 + 4 and 110 ( 6 + 6 ), is:
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Let x1, x2, x3, x4 be the solution of the equation 4x4 + 8x3 - 17x2 - 12x + 9 = 0 and (4 + x12 ) (4 + x22 ) (4 + x32 ) (4 + x42 ) = 12516m. Then the value of m is .
If z1, z2 are two distinct complex numbers such that | z1 - 2z2 12 - z1 z2 | = 2, then
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Let S1 = \z C : |z| 5\, S2 = \z C : Im ( z + 1 - 3 i1 - 3 i ) 0 \ and S3 = \z C : Re(z) 0\. Then the area of the region S1 S2 S3 is :
The number of real solutions of the equation x|x + 5| + 2|x + 7| - 2 = 0 is .
If 2 and 6 are the roots of the equation ax2+bx+1=0, then the quadratic equation, whose roots are 12a+b and 16a+b, is :
Let and be the sum and the product of all the non-zero solutions of the equation ( z)2+|z|=0, z . Then 4( 2+ 2) is equal to :