The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:
- 4 - 13
- 2 - 13
- 2 ( 2 - 13 )
- 12 ( 2 - 13 )
Previous year questions with solutions · 2025 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 19 | 19 | 1 | 4.00% ▼ 5% vs last year |
| 2025 | 20 | 19 | 1.1 | 4.21% |
The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:
The area of the region \(x,y):x2+4x+2 y |x+2| \ is equal to
The area of the region enclosed by the curves y=ex, y=|ex-1| and y-axis is :
If the area of the larger portion bounded between the curves x2+y2=25 and y=|x-1| is 14(b +c), b,c , then b+c is equal to
If the area of the region \(x,y):-1 x 1, 0 y a+e|x|-e-x, a>0 \ is e2+8e+1e, then the value of a is :
The area of the region, inside the circle (x-2 3)2+y2=12 and outside the parabola y2=2 3 x is :
Let f:R be a twice differentiable function such that f(x+y)=f(x)f(y) for all x,y . If f'(0)=4a and f satisfies f''(x)-3af'(x)-f(x)=0, a>0, then the area of the region R=\(x,y) 0 y f(ax), 0 x 2\ is :
Let the function, f(x)= cases-3ax2-2, & x<1\ a2+bx, & x 1 cases be differentiable for all x , where a>1, b . If the area of the region enclosed by y=f(x) and the line y=-20 is + 3, , Z, then the value of + is .
The area of the region enclosed by the curves y=x2-4x+4 and y2=16-8x is :