Ques. 1JEE Main 2024, 8 April (Evening Shift)
The number of distinct real roots of the equation |x + 1||x + 3| - 4|x + 2| + 5 = 0, is
Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 36 | 19 | 1.9 | 7.58% ▲ 2.9% vs last year |
| 2025 | 35 | 19 | 1.8 | 7.37% ▲ 0.5% vs last year |
| 2024 | 44 | 20 | 2.2 | 7.33% |
The number of distinct real roots of the equation |x + 1||x + 3| - 4|x + 2| + 5 = 0, is
The number of distinct real roots of the equation |x||x + 2| - 5|x + 1| - 1 = 0 is .
The number of real solutions of the equation x|x + 5| + 2|x + 7| - 2 = 0 is .
Let a, b, c be the lengths of three sides of a triangle satisfying the condition (a2+b2 )x2-2b(a+c)x+ (b2+c2 )=0. If the set of all possible values of x is the interval ( , ), then 12 ( 2+ 2 ) is equal to .
The number of real solutions of the equation x (x2+3|x|+5|x-1|+6|x-2| )=0 is .