Ques. 1JEE Advanced 2026 (Paper-2)
Let y:(- , ) (0, ) be the solution of the differential equation dydx= e5xy3+y3ex+exy4, satisfying y(0)= 1 2. Then the value of y( e 2) is
- 5+ 352
- 7+ 532
- 7+ 532
- 5+ 352
Differential Equations
Previous year questions with solutions · 2024 – 2026
5Questions
4Papers covered
5.88%Weightage 2026▼ 5.9% vs last year
’24
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 2 | 2 | 1 | 5.88% ▼ 5.9% vs last year |
| 2025 | 2 | 2 | 1 | 6.25% ▲ 112.5% vs last year |
| 2024 | 1 | 2 | 0.5 | 2.94% |
Ques. 2JEE Advanced 2025 (Paper-1)
For all x > 0, let y1(x), y2(x), and y3(x) be the functions satisfying dy1dx - ( x)2y1 = 0, y1(1) = 5, dy2dx - ( x)2y2 = 0, y2(1) = 13, dy3dx - ( 2 - x3x3 )y3 = 0, y3(1) = 35e, respectively. Then x 0+ y1(x)y2(x)y3(x) + 2xe3x x is equal to .